I need to solve these two equations but have absolutely no idea how to do it. Help please? 22. 2x^-2 – x^-1 – 1 = 0 42. f(x) = 2x^2 – 4x + 6

This may be 2 years 1 month late but I will still explain, in the case of others that need help... 2x^-2 - x^-1 -1=0 1) Add 1 to both sides, as shown: 2x^-2 - x^-1 -1=0 +1 +1 Making the equation: 2x^-2 - x^-1 = 1 2) You would then divide both sides of the equation by 2, as shown: 2x^-2 - x^-1 = 1 -- -- 2 2 Making the equation: x^-2 - x^-1 = .5 3)* You would then combine like terms to get: x^-3 = .5 *I am not quite sure if this step is correct, please do say that I am sure about this. If it is something different, please tell me. I am clueless after the 3rd step. But I do wish I helped somewhat. The negative exponets are something I haven't had to deal with. Sorry I was no help, but I tried, and if I am wrong with the whole set up of the equation, please tell me. -William