Can you figure this out? This is the problem: (-x3 + 22x2 - 120x) ÷ (x - 12) And no this is not cheating, im just seeing if you guys can figure this out..

Just want to verify . . . is the equation: (-x^3 + 22x^2 - 120x) ÷ (x - 12) ? If so, there are 2 ways to solve it; long division or synthetic division. Synthetic division would be easier in this case, but it's kind of hard to do on the compy. I'll try . . . (-x^3 + 22x^2 - 120x) ÷ (x - 12) 12|_-1__22__-120__0 .....| ___-12___120__0 ....--------------------- ....._-1__10____0___0 So the answer is -x^2 + 10x. B)

Post edited by: a_girl_made_pure, at: 2008/03/03 21:52

[b]a_girl_made_pure wrote:[/b] [quote]Just want to verify . . . is the equation: (-x^3 + 22x^2 - 120x) ÷ (x - 12) ? If so, there are 2 ways to solve it; long division or synthetic division. Synthetic division would be easier in this case, but it's kind of hard to do on the compy. I'll try . . . (-x^3 + 22x^2 - 120x) ÷ (x - 12) 12|_-1__22__-120__0 .....| ___-12___120__0 ....--------------------- ....._-1__10____0___0 So the answer is -x^2 + 10x. B)<br><br>Post edited by: a_girl_made_pure, at: 2008/03/03 21:52[/quote] Yay. Finally someone tried it, and got it right! Aha. You get some burnt/normal cookies: [img]http://mike.creuzer.com/uploaded_images/SSPX0028-776987.JPG[/img]

[b]Sk8emerica wrote:[/b] [quote] Yay. Finally someone tried it, and got it right! Aha. You get some burnt/normal cookies: [img]http://mike.creuzer.com/uploaded_images/SSPX0028-776987.JPG[/img][/quote] Oh, they look . . . interesting . . . I think I'll pass. :P But thanks anyway. ;)